What are the solutions to the equation x^2-0.4x+4.04=0 ?

The solutions to the equation x^2-0.4x+4.04=0 are x= 1/5+2i,x= 1/5-2i

Find the zeros of x^2-0.4x+4.04=0

The zeros of x^2-0.4x+4.04=0 are x= 1/5+2i,x= 1/5-2i

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x^{2} - 0.4 x + 4.04 = 0

x = \frac{1}{5} + 2 i, x = \frac{1}{5} - 2 i

Solution steps

x^{2} - 0.4 x + 4.04 = 0

Multiply both sides by

100

100 x^{2} - 40 x + 404 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 40 ) \pm ( - 40 ) ^{2} - 4 \cdot 100 \cdot 404}{2 \cdot 100}

Simplify

(- 40)^{2} - 4 \cdot 100 \cdot 404 : 400 i

x_{1, 2} = \frac{- ( - 40 ) \pm 400 i}{2 \cdot 100}

Separate the solutions

x_{1} = \frac{- ( - 40 ) + 400 i}{2 \cdot 100}, x_{2} = \frac{- ( - 40 ) - 400 i}{2 \cdot 100}

x = \frac{- ( - 40 ) + 400 i}{2 \cdot 100} : \frac{1}{5} + 2 i

x = \frac{- ( - 40 ) - 400 i}{2 \cdot 100} : \frac{1}{5} - 2 i

The solutions to the quadratic equation are:

x = \frac{1}{5} + 2 i, x = \frac{1}{5} - 2 i

x^{2} + 1.388 \cdot 1 0^{- 5} x - 8.51 \cdot 1 0^{- 17} = 0

6 x - 3 x^{2} - 3 = 0

- 0.5 x^{2} + 80 x - 250 = 0

\frac{3}{5} x^{2} - 1 = 2

x^{2} - 19 x

What are the solutions to the equation x^2-0.4x+4.04=0 ?
The solutions to the equation x^2-0.4x+4.04=0 are x= 1/5+2i,x= 1/5-2i
Find the zeros of x^2-0.4x+4.04=0
The zeros of x^2-0.4x+4.04=0 are x= 1/5+2i,x= 1/5-2i