What are the solutions to the equation 6x-3x^2-3=0 ?

The solutions to the equation 6x-3x^2-3=0 are x=1

Find the zeros of 6x-3x^2-3=0

The zeros of 6x-3x^2-3=0 are x=1

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6 x - 3 x^{2} - 3 = 0

x = 1

Solution steps

6 x - 3 x^{2} - 3 = 0

Write in the standard form

a x^{2} + b x + c = 0

- 3 x^{2} + 6 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 ( - 3 ) ( - 3 )}{2 ( - 3 )}

6^{2} - 4 (- 3) (- 3) = 0

x_{1, 2} = \frac{- 6 \pm 0}{2 ( - 3 )}

x = \frac{- 6}{2 ( - 3 )}

\frac{- 6}{2 ( - 3 )} = 1

x = 1

The solution to the quadratic equation is:

x = 1

- 0.5 x^{2} + 80 x - 250 = 0

\frac{3}{5} x^{2} - 1 = 2

x^{2} - 19 x

3 x^{2} - x - 2 = 0

- x^{2} + 16 x - 63 = 0

What are the solutions to the equation 6x-3x^2-3=0 ?
The solutions to the equation 6x-3x^2-3=0 are x=1
Find the zeros of 6x-3x^2-3=0
The zeros of 6x-3x^2-3=0 are x=1