What are the solutions to the equation -x^2+16x-63=0 ?

The solutions to the equation -x^2+16x-63=0 are x=7,x=9

Find the zeros of -x^2+16x-63=0

The zeros of -x^2+16x-63=0 are x=7,x=9

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- x^{2} + 16 x - 63 = 0

x = 7, x = 9

Solution steps

- x^{2} + 16 x - 63 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 ( - 1 ) ( - 63 )}{2 ( - 1 )}

1 6^{2} - 4 (- 1) (- 63) = 2

x_{1, 2} = \frac{- 16 \pm 2}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 16 + 2}{2 ( - 1 )}, x_{2} = \frac{- 16 - 2}{2 ( - 1 )}

x = \frac{- 16 + 2}{2 ( - 1 )} : 7

x = \frac{- 16 - 2}{2 ( - 1 )} : 9

The solutions to the quadratic equation are:

x = 7, x = 9

m^{2} - 12 m + 26 = 0

λ^{2} - 5 λ - 6 = 0

3 x^{2} - 1 = - 8 x

x, x^{2} - 12 x + 59 = 0

(y - 3) (y - 2) = 6 (y - 3)

What are the solutions to the equation -x^2+16x-63=0 ?
The solutions to the equation -x^2+16x-63=0 are x=7,x=9
Find the zeros of -x^2+16x-63=0
The zeros of -x^2+16x-63=0 are x=7,x=9