What are the solutions to the equation (y-3)(y-2)=6(y-3) ?

The solutions to the equation (y-3)(y-2)=6(y-3) are y=3,y=8

Find the zeros of (y-3)(y-2)=6(y-3)

The zeros of (y-3)(y-2)=6(y-3) are y=3,y=8

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(y - 3) (y - 2) = 6 (y - 3)

y = 3, y = 8

Solution steps

(y - 3) (y - 2) = 6 (y - 3)

Move

6 (y - 3)

to the left side

(y - 3) (y - 2) - 6 (y - 3) = 0

Factor

(y - 3) (y - 2) - 6 (y - 3) : (y - 3) (y - 8)

(y - 3) (y - 8) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

y - 3 = 0 or y - 8 = 0

Solve

y - 3 = 0 : y = 3

Solve

y - 8 = 0 : y = 8

The solutions to the quadratic equation are:

y = 3, y = 8

3 n^{2} + 7 n - 10 = 12

100 x^{2} = 121

x^{2} + 4 x + 3 = x + 1

x^{2} + a x + 4 a^{2} = 0

16 x^{2} + 24 x - 9 = 0

What are the solutions to the equation (y-3)(y-2)=6(y-3) ?
The solutions to the equation (y-3)(y-2)=6(y-3) are y=3,y=8
Find the zeros of (y-3)(y-2)=6(y-3)
The zeros of (y-3)(y-2)=6(y-3) are y=3,y=8