What are the solutions to the equation 18x^2-39x=15 ?

The solutions to the equation 18x^2-39x=15 are x= 5/2 ,x=-1/3

Find the zeros of 18x^2-39x=15

The zeros of 18x^2-39x=15 are x= 5/2 ,x=-1/3

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18 x^{2} - 39 x = 15

x = \frac{5}{2}, x = - \frac{1}{3}

Decimal Notation

x = 2.5, x = - 0.33333 \dots

Solution steps

18 x^{2} - 39 x = 15

Move

15

to the left side

18 x^{2} - 39 x - 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 39 ) \pm ( - 39 ) ^{2} - 4 \cdot 18 ( - 15 )}{2 \cdot 18}

(- 39)^{2} - 4 \cdot 18 (- 15) = 51

x_{1, 2} = \frac{- ( - 39 ) \pm 51}{2 \cdot 18}

Separate the solutions

x_{1} = \frac{- ( - 39 ) + 51}{2 \cdot 18}, x_{2} = \frac{- ( - 39 ) - 51}{2 \cdot 18}

x = \frac{- ( - 39 ) + 51}{2 \cdot 18} : \frac{5}{2}

x = \frac{- ( - 39 ) - 51}{2 \cdot 18} : - \frac{1}{3}

The solutions to the quadratic equation are:

x = \frac{5}{2}, x = - \frac{1}{3}

(6 x - 5) (4 - 3 x) = 0

(x + 6) (x - 4) = 2 x + 12

5 x - 4 = - x^{2}

2 x^{2} + 5 x = 3

\frac{( x ) ^{2}}{2 \cdot 3 \cdot 1 0 ^{8} \cdot 4 π \cdot 1 0 ^{- 7}} = 5.01 \cdot 1 0^{3}

What are the solutions to the equation 18x^2-39x=15 ?
The solutions to the equation 18x^2-39x=15 are x= 5/2 ,x=-1/3
Find the zeros of 18x^2-39x=15
The zeros of 18x^2-39x=15 are x= 5/2 ,x=-1/3