What are the solutions to the equation a= 1/2 r^2b ?

The solutions to the equation a= 1/2 r^2b are r=sqrt((2a)/b),r=-sqrt((2a)/b);\quad b\ne 0

Find the zeros of a= 1/2 r^2b

The zeros of a= 1/2 r^2b are r=sqrt((2a)/b),r=-sqrt((2a)/b);\quad b\ne 0

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a = \frac{1}{2} r^{2} b

r = \frac{2 a}{b}, r = - \frac{2 a}{b}; b \neq = 0

Solution steps

a = \frac{1}{2} r^{2} b

Switch sides

\frac{1}{2} r^{2} b = a

Multiply both sides by

2

b r^{2} = 2 a

Divide both sides by

b; b \neq = 0

r^{2} = \frac{2 a}{b}; b \neq = 0

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

r = \frac{2 a}{b}, r = - \frac{2 a}{b}; b \neq = 0

(x + 3) x = (6 - x) 2 x

3 x^{2} + x = - 2

1 + x + x^{2} = a (1 + x) + b \cdot (1 + x^{2}) + c \cdot (x + x^{2})

x, 16 x^{2} - 24 x y + 9 y^{2} - 30 x - 40 y = 0

2 x^{2} - 3 x + 20 = 0

What are the solutions to the equation a= 1/2 r^2b ?
The solutions to the equation a= 1/2 r^2b are r=sqrt((2a)/b),r=-sqrt((2a)/b);\quad b\ne 0
Find the zeros of a= 1/2 r^2b
The zeros of a= 1/2 r^2b are r=sqrt((2a)/b),r=-sqrt((2a)/b);\quad b\ne 0