What are the solutions to the equation 4(x+7)^2-49=-13-13 ?

The solutions to the equation 4(x+7)^2-49=-13-13 are x=(sqrt(23))/2-7,x=-(sqrt(23))/2-7

Find the zeros of 4(x+7)^2-49=-13-13

The zeros of 4(x+7)^2-49=-13-13 are x=(sqrt(23))/2-7,x=-(sqrt(23))/2-7

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4 (x + 7)^{2} - 49 = - 13 - 13

x = \frac{23}{2} - 7, x = - \frac{23}{2} - 7

Decimal Notation

x = - 4.60208 \dots, x = - 9.39791 \dots

Solution steps

4 (x + 7)^{2} - 49 = - 13 - 13

Move

49

to the right side

4 (x + 7)^{2} = 23

Divide both sides by

4

(x + 7)^{2} = \frac{23}{4}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 7 = \frac{23}{4} : x = \frac{23}{2} - 7

Solve

x + 7 = - \frac{23}{4} : x = - \frac{23}{2} - 7

The solutions to the quadratic equation are:

x = \frac{23}{2} - 7, x = - \frac{23}{2} - 7

- 10 + 6 x^{2} = 134

3 x^{2} - 8 x + 4 = 0

\frac{1}{2} x^{2} + 2 x + \frac{3}{2} = 0

- \frac{1}{10} (x + 10) (x - 20)

100 x - x^{2} + 800 = 0

What are the solutions to the equation 4(x+7)^2-49=-13-13 ?
The solutions to the equation 4(x+7)^2-49=-13-13 are x=(sqrt(23))/2-7,x=-(sqrt(23))/2-7
Find the zeros of 4(x+7)^2-49=-13-13
The zeros of 4(x+7)^2-49=-13-13 are x=(sqrt(23))/2-7,x=-(sqrt(23))/2-7