What are the solutions to the equation -6x^2-36x+42=0 ?

The solutions to the equation -6x^2-36x+42=0 are x=-7,x=1

Find the zeros of -6x^2-36x+42=0

The zeros of -6x^2-36x+42=0 are x=-7,x=1

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- 6 x^{2} - 36 x + 42 = 0

x = - 7, x = 1

Solution steps

- 6 x^{2} - 36 x + 42 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 36 ) \pm ( - 36 ) ^{2} - 4 ( - 6 ) \cdot 42}{2 ( - 6 )}

(- 36)^{2} - 4 (- 6) \cdot 42 = 48

x_{1, 2} = \frac{- ( - 36 ) \pm 48}{2 ( - 6 )}

Separate the solutions

x_{1} = \frac{- ( - 36 ) + 48}{2 ( - 6 )}, x_{2} = \frac{- ( - 36 ) - 48}{2 ( - 6 )}

x = \frac{- ( - 36 ) + 48}{2 ( - 6 )} : - 7

x = \frac{- ( - 36 ) - 48}{2 ( - 6 )} : 1

The solutions to the quadratic equation are:

x = - 7, x = 1

- x^{2} \cdot 25 = 0

- 0.1 x^{2} - x + 40 = 0.1 x^{2} + 2 x + 20

4 x^{2} - 6 x + 9 = 0

- 2 x^{2} + 4 x + 3 = 0

4 x^{2} - 28 x + 29 = 0

What are the solutions to the equation -6x^2-36x+42=0 ?
The solutions to the equation -6x^2-36x+42=0 are x=-7,x=1
Find the zeros of -6x^2-36x+42=0
The zeros of -6x^2-36x+42=0 are x=-7,x=1