What are the solutions to the equation -6x^2+9x+8=0 ?

The solutions to the equation -6x^2+9x+8=0 are x=-(-9+sqrt(273))/(12),x=(9+sqrt(273))/(12)

Find the zeros of -6x^2+9x+8=0

The zeros of -6x^2+9x+8=0 are x=-(-9+sqrt(273))/(12),x=(9+sqrt(273))/(12)

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- 6 x^{2} + 9 x + 8 = 0

x = - \frac{- 9 + 273}{12}, x = \frac{9 + 273}{12}

Decimal Notation

x = - 0.62689 \dots, x = 2.12689 \dots

Solution steps

- 6 x^{2} + 9 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 ( - 6 ) \cdot 8}{2 ( - 6 )}

9^{2} - 4 (- 6) \cdot 8 = 273

x_{1, 2} = \frac{- 9 \pm 273}{2 ( - 6 )}

Separate the solutions

x_{1} = \frac{- 9 + 273}{2 ( - 6 )}, x_{2} = \frac{- 9 - 273}{2 ( - 6 )}

x = \frac{- 9 + 273}{2 ( - 6 )} : - \frac{- 9 + 273}{12}

x = \frac{- 9 - 273}{2 ( - 6 )} : \frac{9 + 273}{12}

The solutions to the quadratic equation are:

x = - \frac{- 9 + 273}{12}, x = \frac{9 + 273}{12}

\frac{x + x + 1}{2} = (x + 1)^{2} - 300

3 x^{2} = 12 x - 1

2 x^{2} + 3 x - 1 = 0

3 2^{2} = 1 6^{2} + x^{2}

x, x^{2} + y^{2} + z^{2} + x + 8 y + m = 0

What are the solutions to the equation -6x^2+9x+8=0 ?
The solutions to the equation -6x^2+9x+8=0 are x=-(-9+sqrt(273))/(12),x=(9+sqrt(273))/(12)
Find the zeros of -6x^2+9x+8=0
The zeros of -6x^2+9x+8=0 are x=-(-9+sqrt(273))/(12),x=(9+sqrt(273))/(12)