What are the solutions to the equation 32^2=16^2+x^2 ?

The solutions to the equation 32^2=16^2+x^2 are x=16sqrt(3),x=-16sqrt(3)

Find the zeros of 32^2=16^2+x^2

The zeros of 32^2=16^2+x^2 are x=16sqrt(3),x=-16sqrt(3)

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3 2^{2} = 1 6^{2} + x^{2}

x = 163, x = - 163

Decimal Notation

x = 27.71281 \dots, x = - 27.71281 \dots

Solution steps

3 2^{2} = 1 6^{2} + x^{2}

Switch sides

1 6^{2} + x^{2} = 3 2^{2}

Move

1 6^{2}

to the right side

x^{2} = 768

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 768, x = - 768

768 = 163

- 768 = - 163

x = 163, x = - 163

x, x^{2} + y^{2} + z^{2} + x + 8 y + m = 0

- y^{2} + 10 y = 24

x^{2} + 6 x + 3 = 80

4 x^{2} + 28 x + 49 = 5

10 x^{2} + 10 x = 0

What are the solutions to the equation 32^2=16^2+x^2 ?
The solutions to the equation 32^2=16^2+x^2 are x=16sqrt(3),x=-16sqrt(3)
Find the zeros of 32^2=16^2+x^2
The zeros of 32^2=16^2+x^2 are x=16sqrt(3),x=-16sqrt(3)