What are the solutions to the equation 4x^2+28x+49=5 ?

The solutions to the equation 4x^2+28x+49=5 are x=(-7+sqrt(5))/2 ,x=-(7+sqrt(5))/2

Find the zeros of 4x^2+28x+49=5

The zeros of 4x^2+28x+49=5 are x=(-7+sqrt(5))/2 ,x=-(7+sqrt(5))/2

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4 x^{2} + 28 x + 49 = 5

x = \frac{- 7 + 5}{2}, x = - \frac{7 + 5}{2}

Decimal Notation

x = - 2.38196 \dots, x = - 4.61803 \dots

Solution steps

4 x^{2} + 28 x + 49 = 5

Move

5

to the left side

4 x^{2} + 28 x + 44 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 28 \pm 2 8 ^{2} - 4 \cdot 4 \cdot 44}{2 \cdot 4}

2 8^{2} - 4 \cdot 4 \cdot 44 = 45

x_{1, 2} = \frac{- 28 \pm 4 5}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 28 + 4 5}{2 \cdot 4}, x_{2} = \frac{- 28 - 4 5}{2 \cdot 4}

x = \frac{- 28 + 4 5}{2 \cdot 4} : \frac{- 7 + 5}{2}

x = \frac{- 28 - 4 5}{2 \cdot 4} : - \frac{7 + 5}{2}

The solutions to the quadratic equation are:

x = \frac{- 7 + 5}{2}, x = - \frac{7 + 5}{2}

10 x^{2} + 10 x = 0

34.04 = 0.9 \cdot 2 \cdot 0.85 \cdot 210 \cdot x \cdot 0.2 (40 - \frac{x}{2})

34 x + x^{2}

2 z^{2} + 11 z + 15 = 0

s^{2} + 7 s + 8 = 0

What are the solutions to the equation 4x^2+28x+49=5 ?
The solutions to the equation 4x^2+28x+49=5 are x=(-7+sqrt(5))/2 ,x=-(7+sqrt(5))/2
Find the zeros of 4x^2+28x+49=5
The zeros of 4x^2+28x+49=5 are x=(-7+sqrt(5))/2 ,x=-(7+sqrt(5))/2