What are the solutions to the equation 7^2+b^2=12^2 ?

The solutions to the equation 7^2+b^2=12^2 are b=sqrt(95),b=-sqrt(95)

Find the zeros of 7^2+b^2=12^2

The zeros of 7^2+b^2=12^2 are b=sqrt(95),b=-sqrt(95)

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7^{2} + b^{2} = 1 2^{2}

b = 95, b = - 95

Decimal Notation

b = 9.74679 \dots, b = - 9.74679 \dots

Solution steps

7^{2} + b^{2} = 1 2^{2}

Move

7^{2}

to the right side

b^{2} = 95

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

b = 95, b = - 95

x^{2} - 10 x + 4 = 3

2 x^{2} + 7 = - 4 x

x^{2} - 11 x + 56 = 5 x + 13

x^{2} + 13 x = 48

\frac{1}{2} x^{2} = 3 x^{2}

What are the solutions to the equation 7^2+b^2=12^2 ?
The solutions to the equation 7^2+b^2=12^2 are b=sqrt(95),b=-sqrt(95)
Find the zeros of 7^2+b^2=12^2
The zeros of 7^2+b^2=12^2 are b=sqrt(95),b=-sqrt(95)