What are the solutions to the equation 9q^2+6q+1=0 ?

The solutions to the equation 9q^2+6q+1=0 are q=-1/3

Find the zeros of 9q^2+6q+1=0

The zeros of 9q^2+6q+1=0 are q=-1/3

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9 q^{2} + 6 q + 1 = 0

q = - \frac{1}{3}

Decimal Notation

q = - 0.33333 \dots

Solution steps

9 q^{2} + 6 q + 1 = 0

Solve with the quadratic formula

q_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 9 \cdot 1}{2 \cdot 9}

6^{2} - 4 \cdot 9 \cdot 1 = 0

q_{1, 2} = \frac{- 6 \pm 0}{2 \cdot 9}

q = \frac{- 6}{2 \cdot 9}

\frac{- 6}{2 \cdot 9} = - \frac{1}{3}

q = - \frac{1}{3}

The solution to the quadratic equation is:

q = - \frac{1}{3}

300 \cdot x \cdot \frac{x}{2} = 6.644518272 \cdot 1800 (619 - x)

- 7 x^{2} - 9 x - 2 = 0

(3 x - 1) (x + 5) = 0

(4 t - 6)^{2} = 12

2 x^{2} + 2 x - 12 = 0

What are the solutions to the equation 9q^2+6q+1=0 ?
The solutions to the equation 9q^2+6q+1=0 are q=-1/3
Find the zeros of 9q^2+6q+1=0
The zeros of 9q^2+6q+1=0 are q=-1/3