What are the solutions to the equation x^2+((sqrt(7))/4)^2=1 ?

The solutions to the equation x^2+((sqrt(7))/4)^2=1 are x= 3/4 ,x=-3/4

Find the zeros of x^2+((sqrt(7))/4)^2=1

The zeros of x^2+((sqrt(7))/4)^2=1 are x= 3/4 ,x=-3/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} + (\frac{7}{4})^{2} = 1

x = \frac{3}{4}, x = - \frac{3}{4}

Decimal Notation

x = 0.75, x = - 0.75

Solution steps

x^{2} + (\frac{7}{4})^{2} = 1

Expand

x^{2} + (\frac{7}{4})^{2} : x^{2} + \frac{7}{16}

x^{2} + \frac{7}{16} = 1

Move

\frac{7}{16}

to the right side

x^{2} = 1 - \frac{7}{16}

Simplify

1 - \frac{7}{16} : \frac{9}{16}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{9}{16}, x = - \frac{9}{16}

\frac{9}{16} = \frac{3}{4}

- \frac{9}{16} = - \frac{3}{4}

x = \frac{3}{4}, x = - \frac{3}{4}

4 (x - 7)^{2} = 37

x, x^{2} + 11 x + \frac{121}{4} = \frac{125}{4}

0.036 s^{2} + 1200 s + 30000000 = 0

v^{2} - 5 = 8 - 2 v^{2}

3 z^{2} - 42 = 0

What are the solutions to the equation x^2+((sqrt(7))/4)^2=1 ?
The solutions to the equation x^2+((sqrt(7))/4)^2=1 are x= 3/4 ,x=-3/4
Find the zeros of x^2+((sqrt(7))/4)^2=1
The zeros of x^2+((sqrt(7))/4)^2=1 are x= 3/4 ,x=-3/4