What are the solutions to the equation 28x^2+14x+1=0 ?

The solutions to the equation 28x^2+14x+1=0 are x=(-7+sqrt(21))/(28),x=-(7+sqrt(21))/(28)

Find the zeros of 28x^2+14x+1=0

The zeros of 28x^2+14x+1=0 are x=(-7+sqrt(21))/(28),x=-(7+sqrt(21))/(28)

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28 x^{2} + 14 x + 1 = 0

x = \frac{- 7 + 21}{28}, x = - \frac{7 + 21}{28}

Decimal Notation

x = - 0.08633 \dots, x = - 0.41366 \dots

Solution steps

28 x^{2} + 14 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 28 \cdot 1}{2 \cdot 28}

1 4^{2} - 4 \cdot 28 \cdot 1 = 221

x_{1, 2} = \frac{- 14 \pm 2 21}{2 \cdot 28}

Separate the solutions

x_{1} = \frac{- 14 + 2 21}{2 \cdot 28}, x_{2} = \frac{- 14 - 2 21}{2 \cdot 28}

x = \frac{- 14 + 2 21}{2 \cdot 28} : \frac{- 7 + 21}{28}

x = \frac{- 14 - 2 21}{2 \cdot 28} : - \frac{7 + 21}{28}

The solutions to the quadratic equation are:

x = \frac{- 7 + 21}{28}, x = - \frac{7 + 21}{28}

6 x^{2} + 4 x + 1 = 9 x

a^{2} + 3 6^{2} = 3 9^{2}

y, x^{2} + y^{2} = 2 y

x^{2} + 10 x + 25 = 14

16 x^{2} - 5 x + 1 = 0

What are the solutions to the equation 28x^2+14x+1=0 ?
The solutions to the equation 28x^2+14x+1=0 are x=(-7+sqrt(21))/(28),x=-(7+sqrt(21))/(28)
Find the zeros of 28x^2+14x+1=0
The zeros of 28x^2+14x+1=0 are x=(-7+sqrt(21))/(28),x=-(7+sqrt(21))/(28)