What are the solutions to the equation factor 35k^2-22k+7=4 ?

The solutions to the equation factor 35k^2-22k+7=4 are k= 1/5 ,k= 3/7

Find the zeros of factor 35k^2-22k+7=4

The zeros of factor 35k^2-22k+7=4 are k= 1/5 ,k= 3/7

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35 k^{2} - 22 k + 7 = 4

k = \frac{1}{5}, k = \frac{3}{7}

Decimal Notation

k = 0.2, k = 0.42857 \dots

Solution steps

35 k^{2} - 22 k + 7 = 4

Move

4

to the left side

35 k^{2} - 22 k + 3 = 0

Factor

35 k^{2} - 22 k + 3 : (5 k - 1) (7 k - 3)

(5 k - 1) (7 k - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

5 k - 1 = 0 or 7 k - 3 = 0

Solve

5 k - 1 = 0 : k = \frac{1}{5}

Solve

7 k - 3 = 0 : k = \frac{3}{7}

The solutions to the quadratic equation are:

k = \frac{1}{5}, k = \frac{3}{7}

x, f = k - 5 k + 1 x^{2} - 20

6 x^{2} + 24 x - 30 = 810

x^{2} - 15 x = 11 - 5 x

c^{2} = 6^{2} + 5^{2}

x^{2} - 8 = 17

What are the solutions to the equation factor 35k^2-22k+7=4 ?
The solutions to the equation factor 35k^2-22k+7=4 are k= 1/5 ,k= 3/7
Find the zeros of factor 35k^2-22k+7=4
The zeros of factor 35k^2-22k+7=4 are k= 1/5 ,k= 3/7