What are the solutions to the equation x^2-8=41 ?

The solutions to the equation x^2-8=41 are x=7,x=-7

Find the zeros of x^2-8=41

The zeros of x^2-8=41 are x=7,x=-7

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x^{2} - 8 = 41

x = 7, x = - 7

Solution steps

x^{2} - 8 = 41

Move

8

to the right side

x^{2} = 49

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 49, x = - 49

49 = 7

- 49 = - 7

x = 7, x = - 7

x^{2} - 10 x = - 29

x^{2} + 8 x - 24 = 3 x

x, 3 x^{2} + 3 y^{2} + 9 x - 3 y + 21 = 0

- 6 x^{2} - 2 x + 77 = - 7 x^{2} + 6 x + 3

(18 x + 7) (2 x + 5) = (7 x - 6) (4 x + 7) + 21

What are the solutions to the equation x^2-8=41 ?
The solutions to the equation x^2-8=41 are x=7,x=-7
Find the zeros of x^2-8=41
The zeros of x^2-8=41 are x=7,x=-7