What are the solutions to the equation x^2-10x=-29 ?

The solutions to the equation x^2-10x=-29 are x=5+2i,x=5-2i

Find the zeros of x^2-10x=-29

The zeros of x^2-10x=-29 are x=5+2i,x=5-2i

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x^{2} - 10 x = - 29

x = 5 + 2 i, x = 5 - 2 i

Solution steps

x^{2} - 10 x = - 29

Move

29

to the left side

x^{2} - 10 x + 29 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 29}{2 \cdot 1}

Simplify

(- 10)^{2} - 4 \cdot 1 \cdot 29 : 4 i

x_{1, 2} = \frac{- ( - 10 ) \pm 4 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 4 i}{2 \cdot 1}, x_{2} = \frac{- ( - 10 ) - 4 i}{2 \cdot 1}

x = \frac{- ( - 10 ) + 4 i}{2 \cdot 1} : 5 + 2 i

x = \frac{- ( - 10 ) - 4 i}{2 \cdot 1} : 5 - 2 i

The solutions to the quadratic equation are:

x = 5 + 2 i, x = 5 - 2 i

x^{2} + 8 x - 24 = 3 x

x, 3 x^{2} + 3 y^{2} + 9 x - 3 y + 21 = 0

- 6 x^{2} - 2 x + 77 = - 7 x^{2} + 6 x + 3

(18 x + 7) (2 x + 5) = (7 x - 6) (4 x + 7) + 21

12 m^{2} + 40 m + 32 = 0

What are the solutions to the equation x^2-10x=-29 ?
The solutions to the equation x^2-10x=-29 are x=5+2i,x=5-2i
Find the zeros of x^2-10x=-29
The zeros of x^2-10x=-29 are x=5+2i,x=5-2i