What are the solutions to the equation 12m^2+40m+32=0 ?

The solutions to the equation 12m^2+40m+32=0 are m=-4/3 ,m=-2

Find the zeros of 12m^2+40m+32=0

The zeros of 12m^2+40m+32=0 are m=-4/3 ,m=-2

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12 m^{2} + 40 m + 32 = 0

m = - \frac{4}{3}, m = - 2

Decimal Notation

m = - 1.33333 \dots, m = - 2

Solution steps

12 m^{2} + 40 m + 32 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 40 \pm 4 0 ^{2} - 4 \cdot 12 \cdot 32}{2 \cdot 12}

4 0^{2} - 4 \cdot 12 \cdot 32 = 8

m_{1, 2} = \frac{- 40 \pm 8}{2 \cdot 12}

Separate the solutions

m_{1} = \frac{- 40 + 8}{2 \cdot 12}, m_{2} = \frac{- 40 - 8}{2 \cdot 12}

m = \frac{- 40 + 8}{2 \cdot 12} : - \frac{4}{3}

m = \frac{- 40 - 8}{2 \cdot 12} : - 2

The solutions to the quadratic equation are:

m = - \frac{4}{3}, m = - 2

4.905 x^{2} + 2.96852197 x - 4.5 = 0

n^{2} - n - 30 = 0

\frac{7 π}{4} = \frac{3 π}{4} r^{2}

4 p^{2} + 6 = 20 p

24 x - 3 x^{2} = 0

What are the solutions to the equation 12m^2+40m+32=0 ?
The solutions to the equation 12m^2+40m+32=0 are m=-4/3 ,m=-2
Find the zeros of 12m^2+40m+32=0
The zeros of 12m^2+40m+32=0 are m=-4/3 ,m=-2