What are the solutions to the equation 4p^2+6=20p ?

The solutions to the equation 4p^2+6=20p are p=(5+sqrt(19))/2 ,p=(5-sqrt(19))/2

Find the zeros of 4p^2+6=20p

The zeros of 4p^2+6=20p are p=(5+sqrt(19))/2 ,p=(5-sqrt(19))/2

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4 p^{2} + 6 = 20 p

p = \frac{5 + 19}{2}, p = \frac{5 - 19}{2}

Decimal Notation

p = 4.67944 \dots, p = 0.32055 \dots

Solution steps

4 p^{2} + 6 = 20 p

Move

20 p

to the left side

4 p^{2} + 6 - 20 p = 0

Write in the standard form

a x^{2} + b x + c = 0

4 p^{2} - 20 p + 6 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 4 \cdot 6}{2 \cdot 4}

(- 20)^{2} - 4 \cdot 4 \cdot 6 = 419

p_{1, 2} = \frac{- ( - 20 ) \pm 4 19}{2 \cdot 4}

Separate the solutions

p_{1} = \frac{- ( - 20 ) + 4 19}{2 \cdot 4}, p_{2} = \frac{- ( - 20 ) - 4 19}{2 \cdot 4}

p = \frac{- ( - 20 ) + 4 19}{2 \cdot 4} : \frac{5 + 19}{2}

p = \frac{- ( - 20 ) - 4 19}{2 \cdot 4} : \frac{5 - 19}{2}

The solutions to the quadratic equation are:

p = \frac{5 + 19}{2}, p = \frac{5 - 19}{2}

24 x - 3 x^{2} = 0

x, x^{2} + y^{2} - (z - 20)^{2} = 0

6 = a^{2} + 8

(x + 5) (2 x - 3) = 9

2 x^{2} + 7 x - 18 = x^{2}

What are the solutions to the equation 4p^2+6=20p ?
The solutions to the equation 4p^2+6=20p are p=(5+sqrt(19))/2 ,p=(5-sqrt(19))/2
Find the zeros of 4p^2+6=20p
The zeros of 4p^2+6=20p are p=(5+sqrt(19))/2 ,p=(5-sqrt(19))/2