What are the solutions to the equation -16t^2+116t+101=0 ?

The solutions to the equation -16t^2+116t+101=0 are t=-(-29+sqrt(1245))/8 ,t=(29+sqrt(1245))/8

Find the zeros of -16t^2+116t+101=0

The zeros of -16t^2+116t+101=0 are t=-(-29+sqrt(1245))/8 ,t=(29+sqrt(1245))/8

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- 16 t^{2} + 116 t + 101 = 0

t = - \frac{- 29 + 1245}{8}, t = \frac{29 + 1245}{8}

Decimal Notation

t = - 0.78556 \dots, t = 8.03556 \dots

Solution steps

- 16 t^{2} + 116 t + 101 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 116 \pm 11 6 ^{2} - 4 ( - 16 ) \cdot 101}{2 ( - 16 )}

11 6^{2} - 4 (- 16) \cdot 101 = 41245

t_{1, 2} = \frac{- 116 \pm 4 1245}{2 ( - 16 )}

Separate the solutions

t_{1} = \frac{- 116 + 4 1245}{2 ( - 16 )}, t_{2} = \frac{- 116 - 4 1245}{2 ( - 16 )}

t = \frac{- 116 + 4 1245}{2 ( - 16 )} : - \frac{- 29 + 1245}{8}

t = \frac{- 116 - 4 1245}{2 ( - 16 )} : \frac{29 + 1245}{8}

The solutions to the quadratic equation are:

t = - \frac{- 29 + 1245}{8}, t = \frac{29 + 1245}{8}

(12 y - 2 (\frac{18 - 3 y}{4}) y - 3 y^{2}) = 0

(3 x - 1) (x - 2) = 22

2 x^{2} - 9 x = 0

x, x^{2} y + 2 y^{3} = 3 x + 2 y

4 n^{2} - 8 n + 90 = 9

What are the solutions to the equation -16t^2+116t+101=0 ?
The solutions to the equation -16t^2+116t+101=0 are t=-(-29+sqrt(1245))/8 ,t=(29+sqrt(1245))/8
Find the zeros of -16t^2+116t+101=0
The zeros of -16t^2+116t+101=0 are t=-(-29+sqrt(1245))/8 ,t=(29+sqrt(1245))/8