What are the solutions to the equation 4n^2-8n+90=9 ?

The solutions to the equation 4n^2-8n+90=9 are n=1+i(sqrt(77))/2 ,n=1-i(sqrt(77))/2

Find the zeros of 4n^2-8n+90=9

The zeros of 4n^2-8n+90=9 are n=1+i(sqrt(77))/2 ,n=1-i(sqrt(77))/2

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4 n^{2} - 8 n + 90 = 9

n = 1 + i \frac{77}{2}, n = 1 - i \frac{77}{2}

Solution steps

4 n^{2} - 8 n + 90 = 9

Move

9

to the left side

4 n^{2} - 8 n + 81 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 4 \cdot 81}{2 \cdot 4}

Simplify

(- 8)^{2} - 4 \cdot 4 \cdot 81 : 477 i

n_{1, 2} = \frac{- ( - 8 ) \pm 4 77 i}{2 \cdot 4}

Separate the solutions

n_{1} = \frac{- ( - 8 ) + 4 77 i}{2 \cdot 4}, n_{2} = \frac{- ( - 8 ) - 4 77 i}{2 \cdot 4}

n = \frac{- ( - 8 ) + 4 77 i}{2 \cdot 4} : 1 + i \frac{77}{2}

n = \frac{- ( - 8 ) - 4 77 i}{2 \cdot 4} : 1 - i \frac{77}{2}

The solutions to the quadratic equation are:

n = 1 + i \frac{77}{2}, n = 1 - i \frac{77}{2}

x, h + g = x^{2}

36 = 100 - x^{2}

y, y^{2} - 4 y + C = x^{3} + 2 x^{2} - 4 x + C

- 6 x (x - 7) = 4 (x + 7) + 4 x

What are the solutions to the equation 4n^2-8n+90=9 ?
The solutions to the equation 4n^2-8n+90=9 are n=1+i(sqrt(77))/2 ,n=1-i(sqrt(77))/2
Find the zeros of 4n^2-8n+90=9
The zeros of 4n^2-8n+90=9 are n=1+i(sqrt(77))/2 ,n=1-i(sqrt(77))/2