What are the solutions to the equation completesquare (x-4)^2=12 ?

The solutions to the equation completesquare (x-4)^2=12 are x=2sqrt(3)+4,x=-2sqrt(3)+4

Find the zeros of completesquare (x-4)^2=12

The zeros of completesquare (x-4)^2=12 are x=2sqrt(3)+4,x=-2sqrt(3)+4

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(x - 4)^{2} = 12

x = 23 + 4, x = - 23 + 4

Decimal Notation

x = 7.46410 \dots, x = 0.53589 \dots

Solution steps

(x - 4)^{2} = 12

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 4 = 12 : x = 23 + 4

Solve

x - 4 = - 12 : x = - 23 + 4

The solutions to the quadratic equation are:

x = 23 + 4, x = - 23 + 4

21000 = 0.68 \cdot 22 \cdot x \cdot \frac{2.5}{1.4} \cdot (54 - 0.4 x)

\frac{y ^{2}}{2} - 3 = y + 1

\frac{x ^{2} - 6}{2} - \frac{x ^{2} + 4}{4} = 5

2 x^{2} - 18 x = - 28

5 x^{2} = 40 x

What are the solutions to the equation completesquare (x-4)^2=12 ?
The solutions to the equation completesquare (x-4)^2=12 are x=2sqrt(3)+4,x=-2sqrt(3)+4
Find the zeros of completesquare (x-4)^2=12
The zeros of completesquare (x-4)^2=12 are x=2sqrt(3)+4,x=-2sqrt(3)+4