What are the solutions to the equation 717=0.04x^2-7x+900 ?

The solutions to the equation 717=0.04x^2-7x+900 are x=(5(35+sqrt(493)))/2 ,x=(5(35-sqrt(493)))/2

Find the zeros of 717=0.04x^2-7x+900

The zeros of 717=0.04x^2-7x+900 are x=(5(35+sqrt(493)))/2 ,x=(5(35-sqrt(493)))/2

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717 = 0.04 x^{2} - 7 x + 900

x = \frac{5 ( 35 + 493 )}{2}, x = \frac{5 ( 35 - 493 )}{2}

Decimal Notation

x = 143.00900 \dots, x = 31.99099 \dots

Solution steps

717 = 0.04 x^{2} - 7 x + 900

Multiply both sides by

100

71700 = 4 x^{2} - 700 x + 90000

Switch sides

4 x^{2} - 700 x + 90000 = 71700

Move

71700

to the left side

4 x^{2} - 700 x + 18300 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 700 ) \pm ( - 700 ) ^{2} - 4 \cdot 4 \cdot 18300}{2 \cdot 4}

(- 700)^{2} - 4 \cdot 4 \cdot 18300 = 20493

x_{1, 2} = \frac{- ( - 700 ) \pm 20 493}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 700 ) + 20 493}{2 \cdot 4}, x_{2} = \frac{- ( - 700 ) - 20 493}{2 \cdot 4}

x = \frac{- ( - 700 ) + 20 493}{2 \cdot 4} : \frac{5 ( 35 + 493 )}{2}

x = \frac{- ( - 700 ) - 20 493}{2 \cdot 4} : \frac{5 ( 35 - 493 )}{2}

The solutions to the quadratic equation are:

x = \frac{5 ( 35 + 493 )}{2}, x = \frac{5 ( 35 - 493 )}{2}

4 r^{2} - 12 r + 5 = 0

1.13 a^{2} + 3.07 = 3.31 a

x^{2} + \frac{1}{2} x - \frac{3}{16} = 0

- 3 (x + 2)^{2} = - 192

x^{2} + 10 x + 24 = 48

What are the solutions to the equation 717=0.04x^2-7x+900 ?
The solutions to the equation 717=0.04x^2-7x+900 are x=(5(35+sqrt(493)))/2 ,x=(5(35-sqrt(493)))/2
Find the zeros of 717=0.04x^2-7x+900
The zeros of 717=0.04x^2-7x+900 are x=(5(35+sqrt(493)))/2 ,x=(5(35-sqrt(493)))/2