What are the solutions to the equation x^2+10x+24=48 ?

The solutions to the equation x^2+10x+24=48 are x=2,x=-12

Find the zeros of x^2+10x+24=48

The zeros of x^2+10x+24=48 are x=2,x=-12

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x^{2} + 10 x + 24 = 48

x = 2, x = - 12

Solution steps

x^{2} + 10 x + 24 = 48

Move

48

to the left side

x^{2} + 10 x - 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot ( - 24 )}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot (- 24) = 14

x_{1, 2} = \frac{- 10 \pm 14}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 10 + 14}{2 \cdot 1}, x_{2} = \frac{- 10 - 14}{2 \cdot 1}

x = \frac{- 10 + 14}{2 \cdot 1} : 2

x = \frac{- 10 - 14}{2 \cdot 1} : - 12

The solutions to the quadratic equation are:

x = 2, x = - 12

4 x^{2} + 6 x - 7 = 0

x, \frac{x ^{2}}{4} + y^{2} - \frac{z ^{2}}{4} = 1

x^{2} - 15 x + 3 = 0

2800 = 54.72 t + \frac{1}{2} \cdot 9.8 \cdot t^{2}

1.5 x^{2} - 6 x + 4.2 = 0

What are the solutions to the equation x^2+10x+24=48 ?
The solutions to the equation x^2+10x+24=48 are x=2,x=-12
Find the zeros of x^2+10x+24=48
The zeros of x^2+10x+24=48 are x=2,x=-12