What are the solutions to the equation 1.5x^2-6x+4.2=0 ?

The solutions to the equation 1.5x^2-6x+4.2=0 are x=(10+sqrt(30))/5 ,x=(10-sqrt(30))/5

Find the zeros of 1.5x^2-6x+4.2=0

The zeros of 1.5x^2-6x+4.2=0 are x=(10+sqrt(30))/5 ,x=(10-sqrt(30))/5

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1.5 x^{2} - 6 x + 4.2 = 0

x = \frac{10 + 30}{5}, x = \frac{10 - 30}{5}

Decimal Notation

x = 3.09544 \dots, x = 0.90455 \dots

Solution steps

1.5 x^{2} - 6 x + 4.2 = 0

Multiply both sides by

10

15 x^{2} - 60 x + 42 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 60 ) \pm ( - 60 ) ^{2} - 4 \cdot 15 \cdot 42}{2 \cdot 15}

(- 60)^{2} - 4 \cdot 15 \cdot 42 = 630

x_{1, 2} = \frac{- ( - 60 ) \pm 6 30}{2 \cdot 15}

Separate the solutions

x_{1} = \frac{- ( - 60 ) + 6 30}{2 \cdot 15}, x_{2} = \frac{- ( - 60 ) - 6 30}{2 \cdot 15}

x = \frac{- ( - 60 ) + 6 30}{2 \cdot 15} : \frac{10 + 30}{5}

x = \frac{- ( - 60 ) - 6 30}{2 \cdot 15} : \frac{10 - 30}{5}

The solutions to the quadratic equation are:

x = \frac{10 + 30}{5}, x = \frac{10 - 30}{5}

xx = 4

x, (x - a)^{2} + ((m \cdot x + n) - b)^{2} = r^{2}

1.16 x^{2} + 0.64 x - 0.36 = 0

1 = 2 x^{2} + 5 x

\frac{( x \cdot ( \frac{x}{4} + 1 ) )}{2} = 60

What are the solutions to the equation 1.5x^2-6x+4.2=0 ?
The solutions to the equation 1.5x^2-6x+4.2=0 are x=(10+sqrt(30))/5 ,x=(10-sqrt(30))/5
Find the zeros of 1.5x^2-6x+4.2=0
The zeros of 1.5x^2-6x+4.2=0 are x=(10+sqrt(30))/5 ,x=(10-sqrt(30))/5