What are the solutions to the equation 1.16x^2+0.64x-0.36=0 ?

The solutions to the equation 1.16x^2+0.64x-0.36=0 are x=(-8+5sqrt(13))/(29),x=-(8+5sqrt(13))/(29)

Find the zeros of 1.16x^2+0.64x-0.36=0

The zeros of 1.16x^2+0.64x-0.36=0 are x=(-8+5sqrt(13))/(29),x=-(8+5sqrt(13))/(29)

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1.16 x^{2} + 0.64 x - 0.36 = 0

x = \frac{- 8 + 5 13}{29}, x = - \frac{8 + 5 13}{29}

Decimal Notation

x = 0.34578 \dots, x = - 0.89750 \dots

Solution steps

1.16 x^{2} + 0.64 x - 0.36 = 0

Multiply both sides by

100

116 x^{2} + 64 x - 36 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 64 \pm 6 4 ^{2} - 4 \cdot 116 ( - 36 )}{2 \cdot 116}

6 4^{2} - 4 \cdot 116 (- 36) = 4013

x_{1, 2} = \frac{- 64 \pm 40 13}{2 \cdot 116}

Separate the solutions

x_{1} = \frac{- 64 + 40 13}{2 \cdot 116}, x_{2} = \frac{- 64 - 40 13}{2 \cdot 116}

x = \frac{- 64 + 40 13}{2 \cdot 116} : \frac{- 8 + 5 13}{29}

x = \frac{- 64 - 40 13}{2 \cdot 116} : - \frac{8 + 5 13}{29}

The solutions to the quadratic equation are:

x = \frac{- 8 + 5 13}{29}, x = - \frac{8 + 5 13}{29}

1 = 2 x^{2} + 5 x

\frac{( x \cdot ( \frac{x}{4} + 1 ) )}{2} = 60

\frac{x ^{2}}{4} + 3 = 2 (x - 2)

2 a^{2} - 7 a + 3 = 0

2 = x^{2} - 12 x + 32

What are the solutions to the equation 1.16x^2+0.64x-0.36=0 ?
The solutions to the equation 1.16x^2+0.64x-0.36=0 are x=(-8+5sqrt(13))/(29),x=-(8+5sqrt(13))/(29)
Find the zeros of 1.16x^2+0.64x-0.36=0
The zeros of 1.16x^2+0.64x-0.36=0 are x=(-8+5sqrt(13))/(29),x=-(8+5sqrt(13))/(29)