What are the solutions to the equation quadraticformula (x^2)/4+3=2(x-2) ?

The solutions to the equation quadraticformula (x^2)/4+3=2(x-2) are x=4+2sqrt(3)i,x=4-2sqrt(3)i

Find the zeros of quadraticformula (x^2)/4+3=2(x-2)

The zeros of quadraticformula (x^2)/4+3=2(x-2) are x=4+2sqrt(3)i,x=4-2sqrt(3)i

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\frac{x ^{2}}{4} + 3 = 2 (x - 2)

x = 4 + 23 i, x = 4 - 23 i

Solution steps

\frac{x ^{2}}{4} + 3 = 2 (x - 2)

Multiply both sides by

4

x^{2} + 12 = 8 (x - 2)

Expand

8 (x - 2) : 8 x - 16

x^{2} + 12 = 8 x - 16

Move

16

to the left side

x^{2} + 28 = 8 x

Move

8 x

to the left side

x^{2} + 28 - 8 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 8 x + 28 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 28}{2 \cdot 1}

Simplify

(- 8)^{2} - 4 \cdot 1 \cdot 28 : 43 i

x_{1, 2} = \frac{- ( - 8 ) \pm 4 3 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 4 3 i}{2 \cdot 1}, x_{2} = \frac{- ( - 8 ) - 4 3 i}{2 \cdot 1}

x = \frac{- ( - 8 ) + 4 3 i}{2 \cdot 1} : 4 + 23 i

x = \frac{- ( - 8 ) - 4 3 i}{2 \cdot 1} : 4 - 23 i

The solutions to the quadratic equation are:

x = 4 + 23 i, x = 4 - 23 i

2 a^{2} - 7 a + 3 = 0

2 = x^{2} - 12 x + 32

2 x^{2} + 3 x - 3 = 0

x, (m - 2) x^{2} + (n - 1) x + (p - 3) = 0

5 r^{2} - 6 r + 1 = 0

What are the solutions to the equation quadraticformula (x^2)/4+3=2(x-2) ?
The solutions to the equation quadraticformula (x^2)/4+3=2(x-2) are x=4+2sqrt(3)i,x=4-2sqrt(3)i
Find the zeros of quadraticformula (x^2)/4+3=2(x-2)
The zeros of quadraticformula (x^2)/4+3=2(x-2) are x=4+2sqrt(3)i,x=4-2sqrt(3)i