What are the solutions to the equation (sqrt(5))^2=a^2+(2a)^2 ?

The solutions to the equation (sqrt(5))^2=a^2+(2a)^2 are a=1,a=-1

Find the zeros of (sqrt(5))^2=a^2+(2a)^2

The zeros of (sqrt(5))^2=a^2+(2a)^2 are a=1,a=-1

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(5)^{2} = a^{2} + (2 a)^{2}

a = 1, a = - 1

Solution steps

(5)^{2} = a^{2} + (2 a)^{2}

Expand

(5)^{2} : 5

Expand

a^{2} + (2 a)^{2} : 5 a^{2}

5 = 5 a^{2}

Switch sides

5 a^{2} = 5

Move

5

to the left side

5 a^{2} - 5 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 0 \pm 0 ^{2} - 4 \cdot 5 ( - 5 )}{2 \cdot 5}

0^{2} - 4 \cdot 5 (- 5) = 10

a_{1, 2} = \frac{- 0 \pm 10}{2 \cdot 5}

Separate the solutions

a_{1} = \frac{- 0 + 10}{2 \cdot 5}, a_{2} = \frac{- 0 - 10}{2 \cdot 5}

a = \frac{- 0 + 10}{2 \cdot 5} : 1

a = \frac{- 0 - 10}{2 \cdot 5} : - 1

The solutions to the quadratic equation are:

a = 1, a = - 1

30 (25 - t^{2}) = 500

t^{2} - 6 t - 4 = 0

3 = x (x + 2)

4 a^{2} + 20 a^{2} + 9 = 0

x^{2} - 12 + 32 = 0

What are the solutions to the equation (sqrt(5))^2=a^2+(2a)^2 ?
The solutions to the equation (sqrt(5))^2=a^2+(2a)^2 are a=1,a=-1
Find the zeros of (sqrt(5))^2=a^2+(2a)^2
The zeros of (sqrt(5))^2=a^2+(2a)^2 are a=1,a=-1