What are the solutions to the equation -3x^2+8x=((-3)-(-3))/((4)-(0)) ?

The solutions to the equation -3x^2+8x=((-3)-(-3))/((4)-(0)) are x=0,x= 8/3

Find the zeros of -3x^2+8x=((-3)-(-3))/((4)-(0))

The zeros of -3x^2+8x=((-3)-(-3))/((4)-(0)) are x=0,x= 8/3

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- 3 x^{2} + 8 x = \frac{( - 3 ) - ( - 3 )}{( 4 ) - ( 0 )}

x = 0, x = \frac{8}{3}

Decimal Notation

x = 0, x = 2.66666 \dots

Solution steps

- 3 x^{2} + 8 x = \frac{( - 3 ) - ( - 3 )}{( 4 ) - ( 0 )}

Simplify

(4) - (0) : 4

- 3 x^{2} + 8 x = \frac{( - 3 ) - ( - 3 )}{4}

Multiply both sides by

4

- 12 x^{2} + 32 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 32 \pm 3 2 ^{2} - 4 ( - 12 ) \cdot 0}{2 ( - 12 )}

3 2^{2} - 4 (- 12) \cdot 0 = 32

x_{1, 2} = \frac{- 32 \pm 32}{2 ( - 12 )}

Separate the solutions

x_{1} = \frac{- 32 + 32}{2 ( - 12 )}, x_{2} = \frac{- 32 - 32}{2 ( - 12 )}

x = \frac{- 32 + 32}{2 ( - 12 )} : 0

x = \frac{- 32 - 32}{2 ( - 12 )} : \frac{8}{3}

The solutions to the quadratic equation are:

x = 0, x = \frac{8}{3}

x, 2 + (2 x + 3)^{2} - x = 0

16 u^{2} - 9 = 0

3 x^{2} - 49 x + 200 = 0

\frac{1}{50} x^{2} - \frac{2}{5} x + 1 = 7

x^{2} + 16 x + 20 = 0

What are the solutions to the equation -3x^2+8x=((-3)-(-3))/((4)-(0)) ?
The solutions to the equation -3x^2+8x=((-3)-(-3))/((4)-(0)) are x=0,x= 8/3
Find the zeros of -3x^2+8x=((-3)-(-3))/((4)-(0))
The zeros of -3x^2+8x=((-3)-(-3))/((4)-(0)) are x=0,x= 8/3