What are the solutions to the equation 1/50 x^2-2/5 x+1=7 ?

The solutions to the equation 1/50 x^2-2/5 x+1=7 are x=30,x=-10

Find the zeros of 1/50 x^2-2/5 x+1=7

The zeros of 1/50 x^2-2/5 x+1=7 are x=30,x=-10

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\frac{1}{50} x^{2} - \frac{2}{5} x + 1 = 7

x = 30, x = - 10

Solution steps

\frac{1}{50} x^{2} - \frac{2}{5} x + 1 = 7

Find Least Common Multiplier of

50, 5 : 50

Multiply by LCM=

50

\frac{1}{50} x^{2} \cdot 50 - \frac{2}{5} x \cdot 50 + 1 \cdot 50 = 7 \cdot 50

Simplify

x^{2} - 20 x + 50 = 350

Move

350

to the left side

x^{2} - 20 x - 300 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 1 \cdot ( - 300 )}{2 \cdot 1}

(- 20)^{2} - 4 \cdot 1 \cdot (- 300) = 40

x_{1, 2} = \frac{- ( - 20 ) \pm 40}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 20 ) + 40}{2 \cdot 1}, x_{2} = \frac{- ( - 20 ) - 40}{2 \cdot 1}

x = \frac{- ( - 20 ) + 40}{2 \cdot 1} : 30

x = \frac{- ( - 20 ) - 40}{2 \cdot 1} : - 10

The solutions to the quadratic equation are:

x = 30, x = - 10

x^{2} + 16 x + 20 = 0

p^{2} - 12 p + 9 = 0

x, z = 5 y x^{2}

2200 - x^{2} = 400 + x^{2}

2 - \frac{x ^{2}}{2} = 0

What are the solutions to the equation 1/50 x^2-2/5 x+1=7 ?
The solutions to the equation 1/50 x^2-2/5 x+1=7 are x=30,x=-10
Find the zeros of 1/50 x^2-2/5 x+1=7
The zeros of 1/50 x^2-2/5 x+1=7 are x=30,x=-10