What are the solutions to the equation 4x^2-19x=5 ?

The solutions to the equation 4x^2-19x=5 are x=5,x=-1/4

Find the zeros of 4x^2-19x=5

The zeros of 4x^2-19x=5 are x=5,x=-1/4

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4 x^{2} - 19 x = 5

x = 5, x = - \frac{1}{4}

Decimal Notation

x = 5, x = - 0.25

Solution steps

4 x^{2} - 19 x = 5

Move

5

to the left side

4 x^{2} - 19 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 19 ) \pm ( - 19 ) ^{2} - 4 \cdot 4 ( - 5 )}{2 \cdot 4}

(- 19)^{2} - 4 \cdot 4 (- 5) = 21

x_{1, 2} = \frac{- ( - 19 ) \pm 21}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 19 ) + 21}{2 \cdot 4}, x_{2} = \frac{- ( - 19 ) - 21}{2 \cdot 4}

x = \frac{- ( - 19 ) + 21}{2 \cdot 4} : 5

x = \frac{- ( - 19 ) - 21}{2 \cdot 4} : - \frac{1}{4}

The solutions to the quadratic equation are:

x = 5, x = - \frac{1}{4}

2 ((y + 5) y) = (y + 10) (y + 5)

x, x^{2} + 2 x y - 9 x - 6 y + 18 = 0

x^{2} - 50 \cdot 1 0^{- 6} x + \frac{4}{9} \cdot 1 0^{- 9} = 0

(x - 6)^{2} - 72 = 0

x^{2} - 4 x - 45 = 0

What are the solutions to the equation 4x^2-19x=5 ?
The solutions to the equation 4x^2-19x=5 are x=5,x=-1/4
Find the zeros of 4x^2-19x=5
The zeros of 4x^2-19x=5 are x=5,x=-1/4