What are the solutions to the equation solvefor x,x^2+2xy-9x-6y+18=0 ?

The solutions to the equation solvefor x,x^2+2xy-9x-6y+18=0 are x=3,x=2(-y+3)

Find the zeros of solvefor x,x^2+2xy-9x-6y+18=0

The zeros of solvefor x,x^2+2xy-9x-6y+18=0 are x=3,x=2(-y+3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solve for

x, x^{2} + 2 x y - 9 x - 6 y + 18 = 0

x = 3, x = 2 (- y + 3)

Solution steps

x^{2} + 2 x y - 9 x - 6 y + 18 = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + (2 y - 9) x - 6 y + 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( 2 y - 9 ) \pm ( 2 y - 9 ) ^{2} - 4 \cdot 1 \cdot ( - 6 y + 18 )}{2 \cdot 1}

Simplify

(2 y - 9)^{2} - 4 \cdot 1 \cdot (- 6 y + 18) : 2 y - 3

x_{1, 2} = \frac{- ( 2 y - 9 ) \pm ( 2 y - 3 )}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( 2 y - 9 ) + 2 y - 3}{2 \cdot 1}, x_{2} = \frac{- ( 2 y - 9 ) - ( 2 y - 3 )}{2 \cdot 1}

x = \frac{- ( 2 y - 9 ) + 2 y - 3}{2 \cdot 1} : 3

x = \frac{- ( 2 y - 9 ) - ( 2 y - 3 )}{2 \cdot 1} : 2 (- y + 3)

The solutions to the quadratic equation are:

x = 3, x = 2 (- y + 3)

x^{2} - 50 \cdot 1 0^{- 6} x + \frac{4}{9} \cdot 1 0^{- 9} = 0

(x - 6)^{2} - 72 = 0

x^{2} - 4 x - 45 = 0

- 2 x^{2} + 8 x - 3 = 4

2 x^{2} + 6 x + 3 = 0

What are the solutions to the equation solvefor x,x^2+2xy-9x-6y+18=0 ?
The solutions to the equation solvefor x,x^2+2xy-9x-6y+18=0 are x=3,x=2(-y+3)
Find the zeros of solvefor x,x^2+2xy-9x-6y+18=0
The zeros of solvefor x,x^2+2xy-9x-6y+18=0 are x=3,x=2(-y+3)