What are the solutions to the equation -2x^2+8x-3=4 ?

The solutions to the equation -2x^2+8x-3=4 are x=(4-sqrt(2))/2 ,x=(4+sqrt(2))/2

Find the zeros of -2x^2+8x-3=4

The zeros of -2x^2+8x-3=4 are x=(4-sqrt(2))/2 ,x=(4+sqrt(2))/2

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- 2 x^{2} + 8 x - 3 = 4

x = \frac{4 - 2}{2}, x = \frac{4 + 2}{2}

Decimal Notation

x = 1.29289 \dots, x = 2.70710 \dots

Solution steps

- 2 x^{2} + 8 x - 3 = 4

Move

4

to the left side

- 2 x^{2} + 8 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 ( - 2 ) ( - 7 )}{2 ( - 2 )}

8^{2} - 4 (- 2) (- 7) = 22

x_{1, 2} = \frac{- 8 \pm 2 2}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 8 + 2 2}{2 ( - 2 )}, x_{2} = \frac{- 8 - 2 2}{2 ( - 2 )}

x = \frac{- 8 + 2 2}{2 ( - 2 )} : \frac{4 - 2}{2}

x = \frac{- 8 - 2 2}{2 ( - 2 )} : \frac{4 + 2}{2}

The solutions to the quadratic equation are:

x = \frac{4 - 2}{2}, x = \frac{4 + 2}{2}

2 x^{2} + 6 x + 3 = 0

x^{2} + 445 x - 2225 = 0

x, 4 x^{2} + 4 y^{2} = z^{2}

- 3 x^{2} - 3 x + 10

a^{2} = 3^{2} + 4^{2}

What are the solutions to the equation -2x^2+8x-3=4 ?
The solutions to the equation -2x^2+8x-3=4 are x=(4-sqrt(2))/2 ,x=(4+sqrt(2))/2
Find the zeros of -2x^2+8x-3=4
The zeros of -2x^2+8x-3=4 are x=(4-sqrt(2))/2 ,x=(4+sqrt(2))/2