What are the solutions to the equation 5r^2+27r-18=0 ?

The solutions to the equation 5r^2+27r-18=0 are r= 3/5 ,r=-6

Find the zeros of 5r^2+27r-18=0

The zeros of 5r^2+27r-18=0 are r= 3/5 ,r=-6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

5 r^{2} + 27 r - 18 = 0

r = \frac{3}{5}, r = - 6

Decimal Notation

r = 0.6, r = - 6

Solution steps

5 r^{2} + 27 r - 18 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 27 \pm 2 7 ^{2} - 4 \cdot 5 ( - 18 )}{2 \cdot 5}

2 7^{2} - 4 \cdot 5 (- 18) = 33

r_{1, 2} = \frac{- 27 \pm 33}{2 \cdot 5}

Separate the solutions

r_{1} = \frac{- 27 + 33}{2 \cdot 5}, r_{2} = \frac{- 27 - 33}{2 \cdot 5}

r = \frac{- 27 + 33}{2 \cdot 5} : \frac{3}{5}

r = \frac{- 27 - 33}{2 \cdot 5} : - 6

The solutions to the quadratic equation are:

r = \frac{3}{5}, r = - 6

150000 = 200 - 20 t + 2 t^{2}

x, 1 - y x + \frac{y ^{2} x ^{2}}{2} = 0

5 x^{2} - 6 x - 11 = 0

m^{2} + 2 m + 16 = 0

x^{2} = 3 + 22

What are the solutions to the equation 5r^2+27r-18=0 ?
The solutions to the equation 5r^2+27r-18=0 are r= 3/5 ,r=-6
Find the zeros of 5r^2+27r-18=0
The zeros of 5r^2+27r-18=0 are r= 3/5 ,r=-6