What are the solutions to the equation 150000=200-20t+2t^2 ?

The solutions to the equation 150000=200-20t+2t^2 are t=5(1+9sqrt(37)),t=5(1-9sqrt(37))

Find the zeros of 150000=200-20t+2t^2

The zeros of 150000=200-20t+2t^2 are t=5(1+9sqrt(37)),t=5(1-9sqrt(37))

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150000 = 200 - 20 t + 2 t^{2}

t = 5 (1 + 937), t = 5 (1 - 937)

Decimal Notation

t = 278.72431 \dots, t = - 268.72431 \dots

Solution steps

150000 = 200 - 20 t + 2 t^{2}

Switch sides

200 - 20 t + 2 t^{2} = 150000

Move

150000

to the left side

2 t^{2} - 20 t - 149800 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 2 ( - 149800 )}{2 \cdot 2}

(- 20)^{2} - 4 \cdot 2 (- 149800) = 18037

t_{1, 2} = \frac{- ( - 20 ) \pm 180 37}{2 \cdot 2}

Separate the solutions

t_{1} = \frac{- ( - 20 ) + 180 37}{2 \cdot 2}, t_{2} = \frac{- ( - 20 ) - 180 37}{2 \cdot 2}

t = \frac{- ( - 20 ) + 180 37}{2 \cdot 2} : 5 (1 + 937)

t = \frac{- ( - 20 ) - 180 37}{2 \cdot 2} : 5 (1 - 937)

The solutions to the quadratic equation are:

t = 5 (1 + 937), t = 5 (1 - 937)

x, 1 - y x + \frac{y ^{2} x ^{2}}{2} = 0

5 x^{2} - 6 x - 11 = 0

m^{2} + 2 m + 16 = 0

x^{2} = 3 + 22

x^{2} + 5 x + 9 = - 3 x - 3

What are the solutions to the equation 150000=200-20t+2t^2 ?
The solutions to the equation 150000=200-20t+2t^2 are t=5(1+9sqrt(37)),t=5(1-9sqrt(37))
Find the zeros of 150000=200-20t+2t^2
The zeros of 150000=200-20t+2t^2 are t=5(1+9sqrt(37)),t=5(1-9sqrt(37))