What are the solutions to the equation solvefor x,5x^2-3x-2=0 ?

The solutions to the equation solvefor x,5x^2-3x-2=0 are x=1,x=-2/5

Find the zeros of solvefor x,5x^2-3x-2=0

The zeros of solvefor x,5x^2-3x-2=0 are x=1,x=-2/5

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x, 5 x^{2} - 3 x - 2 = 0

x = 1, x = - \frac{2}{5}

Decimal Notation

x = 1, x = - 0.4

Solution steps

5 x^{2} - 3 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 5 ( - 2 )}{2 \cdot 5}

(- 3)^{2} - 4 \cdot 5 (- 2) = 7

x_{1, 2} = \frac{- ( - 3 ) \pm 7}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 7}{2 \cdot 5}, x_{2} = \frac{- ( - 3 ) - 7}{2 \cdot 5}

x = \frac{- ( - 3 ) + 7}{2 \cdot 5} : 1

x = \frac{- ( - 3 ) - 7}{2 \cdot 5} : - \frac{2}{5}

The solutions to the quadratic equation are:

x = 1, x = - \frac{2}{5}

x, x^{2} - 2 x + y^{2} - 4 y - z^{2} + 6 z = 0

5 x^{2} = 14

c^{2} - 2 c + 0.1 = 0

w, 36 + 96 = 5.625 w^{2}

x, 4 x^{2} + 9 y^{2} - 36 z = 0

What are the solutions to the equation solvefor x,5x^2-3x-2=0 ?
The solutions to the equation solvefor x,5x^2-3x-2=0 are x=1,x=-2/5
Find the zeros of solvefor x,5x^2-3x-2=0
The zeros of solvefor x,5x^2-3x-2=0 are x=1,x=-2/5