What are the solutions to the equation c^2-2c+0.1=0 ?

The solutions to the equation c^2-2c+0.1=0 are c=(10+3sqrt(10))/(10),c=(10-3sqrt(10))/(10)

Find the zeros of c^2-2c+0.1=0

The zeros of c^2-2c+0.1=0 are c=(10+3sqrt(10))/(10),c=(10-3sqrt(10))/(10)

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c^{2} - 2 c + 0.1 = 0

c = \frac{10 + 3 10}{10}, c = \frac{10 - 3 10}{10}

Decimal Notation

c = 1.94868 \dots, c = 0.05131 \dots

Solution steps

c^{2} - 2 c + 0.1 = 0

Multiply both sides by

10

10 c^{2} - 20 c + 1 = 0

Solve with the quadratic formula

c_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 10 \cdot 1}{2 \cdot 10}

(- 20)^{2} - 4 \cdot 10 \cdot 1 = 610

c_{1, 2} = \frac{- ( - 20 ) \pm 6 10}{2 \cdot 10}

Separate the solutions

c_{1} = \frac{- ( - 20 ) + 6 10}{2 \cdot 10}, c_{2} = \frac{- ( - 20 ) - 6 10}{2 \cdot 10}

c = \frac{- ( - 20 ) + 6 10}{2 \cdot 10} : \frac{10 + 3 10}{10}

c = \frac{- ( - 20 ) - 6 10}{2 \cdot 10} : \frac{10 - 3 10}{10}

The solutions to the quadratic equation are:

c = \frac{10 + 3 10}{10}, c = \frac{10 - 3 10}{10}

w, 36 + 96 = 5.625 w^{2}

x, 4 x^{2} + 9 y^{2} - 36 z = 0

(7 + X)^{2} + (7 - X)^{2} = 130

- x^{2} + 4 x + 36 = 0

4 x^{2} - 17 x + 11 = 0

What are the solutions to the equation c^2-2c+0.1=0 ?
The solutions to the equation c^2-2c+0.1=0 are c=(10+3sqrt(10))/(10),c=(10-3sqrt(10))/(10)
Find the zeros of c^2-2c+0.1=0
The zeros of c^2-2c+0.1=0 are c=(10+3sqrt(10))/(10),c=(10-3sqrt(10))/(10)