What are the solutions to the equation solvefor x,y=x^2-2 ?

The solutions to the equation solvefor x,y=x^2-2 are x=sqrt(y+2),x=-sqrt(y+2)

Find the zeros of solvefor x,y=x^2-2

The zeros of solvefor x,y=x^2-2 are x=sqrt(y+2),x=-sqrt(y+2)

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solve for

x, y = x^{2} - 2

x = y + 2, x = - y + 2

Solution steps

y = x^{2} - 2

Switch sides

x^{2} - 2 = y

Move

2

to the right side

x^{2} = y + 2

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = y + 2, x = - y + 2

x (x + 7) = 690

2 x (3 x + 5) = - 1 + 4 x

\frac{1}{2} x^{2} - 4 x + 3

x^{2} + a^{2} x^{2} - 4 x a^{2} + 4 a^{2} = 1

- 11 x + 5 + 2 x^{2} = 0

What are the solutions to the equation solvefor x,y=x^2-2 ?
The solutions to the equation solvefor x,y=x^2-2 are x=sqrt(y+2),x=-sqrt(y+2)
Find the zeros of solvefor x,y=x^2-2
The zeros of solvefor x,y=x^2-2 are x=sqrt(y+2),x=-sqrt(y+2)