What are the solutions to the equation p^2-10=3p ?

The solutions to the equation p^2-10=3p are p=5,p=-2

Find the zeros of p^2-10=3p

The zeros of p^2-10=3p are p=5,p=-2

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p^{2} - 10 = 3 p

p = 5, p = - 2

Solution steps

p^{2} - 10 = 3 p

Move

3 p

to the left side

p^{2} - 10 - 3 p = 0

Write in the standard form

a x^{2} + b x + c = 0

p^{2} - 3 p - 10 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot ( - 10 )}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot (- 10) = 7

p_{1, 2} = \frac{- ( - 3 ) \pm 7}{2 \cdot 1}

Separate the solutions

p_{1} = \frac{- ( - 3 ) + 7}{2 \cdot 1}, p_{2} = \frac{- ( - 3 ) - 7}{2 \cdot 1}

p = \frac{- ( - 3 ) + 7}{2 \cdot 1} : 5

p = \frac{- ( - 3 ) - 7}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

p = 5, p = - 2

- 3 x^{2} + 9 x - 2 = 0

- 4 x^{2} + 3 = 5 x^{2} - 6 x - 4

z^{2} - 0.0952 z - 0.9048 = 0

x^{2} - 8 x + 20 = 0

4.9 t^{2} - 11 t + 241 = 0

What are the solutions to the equation p^2-10=3p ?
The solutions to the equation p^2-10=3p are p=5,p=-2
Find the zeros of p^2-10=3p
The zeros of p^2-10=3p are p=5,p=-2