What are the solutions to the equation 0=6(x-1)(x+2) ?

The solutions to the equation 0=6(x-1)(x+2) are x=1,x=-2

Find the zeros of 0=6(x-1)(x+2)

The zeros of 0=6(x-1)(x+2) are x=1,x=-2

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0 = 6 (x - 1) (x + 2)

x = 1, x = - 2

Solution steps

0 = 6 (x - 1) (x + 2)

Switch sides

6 (x - 1) (x + 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or x + 2 = 0

Solve

x - 1 = 0 : x = 1

Solve

x + 2 = 0 : x = - 2

The solutions to the quadratic equation are:

x = 1, x = - 2

a, - 6 a^{2} + 12 - 12 ab - 6 b = 0

x^{2} = 2 1^{2} + 2 0^{2}

x, z = 3 x^{2} - 2 x y + y^{2} + 2 x + 2 y + 9

y^{2} - 5 y - 36 = 0

73 = 3 q^{2} - 40 q + 150

What are the solutions to the equation 0=6(x-1)(x+2) ?
The solutions to the equation 0=6(x-1)(x+2) are x=1,x=-2
Find the zeros of 0=6(x-1)(x+2)
The zeros of 0=6(x-1)(x+2) are x=1,x=-2