What are the solutions to the equation 4x^2-14x+2=0 ?

The solutions to the equation 4x^2-14x+2=0 are x=(7+sqrt(41))/4 ,x=(7-sqrt(41))/4

Find the zeros of 4x^2-14x+2=0

The zeros of 4x^2-14x+2=0 are x=(7+sqrt(41))/4 ,x=(7-sqrt(41))/4

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4 x^{2} - 14 x + 2 = 0

x = \frac{7 + 41}{4}, x = \frac{7 - 41}{4}

Decimal Notation

x = 3.35078 \dots, x = 0.14921 \dots

Solution steps

4 x^{2} - 14 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 4 \cdot 2}{2 \cdot 4}

(- 14)^{2} - 4 \cdot 4 \cdot 2 = 241

x_{1, 2} = \frac{- ( - 14 ) \pm 2 41}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 14 ) + 2 41}{2 \cdot 4}, x_{2} = \frac{- ( - 14 ) - 2 41}{2 \cdot 4}

x = \frac{- ( - 14 ) + 2 41}{2 \cdot 4} : \frac{7 + 41}{4}

x = \frac{- ( - 14 ) - 2 41}{2 \cdot 4} : \frac{7 - 41}{4}

The solutions to the quadratic equation are:

x = \frac{7 + 41}{4}, x = \frac{7 - 41}{4}

0.3 q^{2} + q - 40 = 0

4 d^{2} + 9 d - 7 = 22

- x^{2} + 10 x

x, y^{2} - x y + x^{2} = 8

(x - 3)^{2} = 9 x

What are the solutions to the equation 4x^2-14x+2=0 ?
The solutions to the equation 4x^2-14x+2=0 are x=(7+sqrt(41))/4 ,x=(7-sqrt(41))/4
Find the zeros of 4x^2-14x+2=0
The zeros of 4x^2-14x+2=0 are x=(7+sqrt(41))/4 ,x=(7-sqrt(41))/4