What are the solutions to the equation x^2-x-400=0 ?

The solutions to the equation x^2-x-400=0 are x=(1+sqrt(1601))/2 ,x=(1-sqrt(1601))/2

Find the zeros of x^2-x-400=0

The zeros of x^2-x-400=0 are x=(1+sqrt(1601))/2 ,x=(1-sqrt(1601))/2

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x^{2} - x - 400 = 0

x = \frac{1 + 1601}{2}, x = \frac{1 - 1601}{2}

Decimal Notation

x = 20.50624 \dots, x = - 19.50624 \dots

Solution steps

x^{2} - x - 400 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 400 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 400) = 1601

x_{1, 2} = \frac{- ( - 1 ) \pm 1601}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 1601}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 1601}{2 \cdot 1}

x = \frac{- ( - 1 ) + 1601}{2 \cdot 1} : \frac{1 + 1601}{2}

x = \frac{- ( - 1 ) - 1601}{2 \cdot 1} : \frac{1 - 1601}{2}

The solutions to the quadratic equation are:

x = \frac{1 + 1601}{2}, x = \frac{1 - 1601}{2}

x, z^{2} = x^{2} + 7.5 y^{2}

2^{2} + - 1 + x^{2} = 2

125 x^{2} + 20 = 0

x, 9 x^{2} + 16 y^{2} = 0

l (q) = 5 q^{2} - 8 q + 12

What are the solutions to the equation x^2-x-400=0 ?
The solutions to the equation x^2-x-400=0 are x=(1+sqrt(1601))/2 ,x=(1-sqrt(1601))/2
Find the zeros of x^2-x-400=0
The zeros of x^2-x-400=0 are x=(1+sqrt(1601))/2 ,x=(1-sqrt(1601))/2