What are the solutions to the equation solvefor u,3u^2-u-3=0 ?

The solutions to the equation solvefor u,3u^2-u-3=0 are u=(1+sqrt(37))/6 ,u=(1-sqrt(37))/6

Find the zeros of solvefor u,3u^2-u-3=0

The zeros of solvefor u,3u^2-u-3=0 are u=(1+sqrt(37))/6 ,u=(1-sqrt(37))/6

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u, 3 u^{2} - u - 3 = 0

u = \frac{1 + 37}{6}, u = \frac{1 - 37}{6}

Decimal Notation

u = 1.18046 \dots, u = - 0.84712 \dots

Solution steps

3 u^{2} - u - 3 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 3 ( - 3 )}{2 \cdot 3}

(- 1)^{2} - 4 \cdot 3 (- 3) = 37

u_{1, 2} = \frac{- ( - 1 ) \pm 37}{2 \cdot 3}

Separate the solutions

u_{1} = \frac{- ( - 1 ) + 37}{2 \cdot 3}, u_{2} = \frac{- ( - 1 ) - 37}{2 \cdot 3}

u = \frac{- ( - 1 ) + 37}{2 \cdot 3} : \frac{1 + 37}{6}

u = \frac{- ( - 1 ) - 37}{2 \cdot 3} : \frac{1 - 37}{6}

The solutions to the quadratic equation are:

u = \frac{1 + 37}{6}, u = \frac{1 - 37}{6}

x + x^{2} - 90 = 0

x^{2} + 17 x - 2 = 0

x^{2} + \frac{1}{3} x + 1 = 0

a^{2} = 9 + 16

p^{2} + 42 = 13 p

What are the solutions to the equation solvefor u,3u^2-u-3=0 ?
The solutions to the equation solvefor u,3u^2-u-3=0 are u=(1+sqrt(37))/6 ,u=(1-sqrt(37))/6
Find the zeros of solvefor u,3u^2-u-3=0
The zeros of solvefor u,3u^2-u-3=0 are u=(1+sqrt(37))/6 ,u=(1-sqrt(37))/6