What are the solutions to the equation solvefor m,m^2-15m+56=0 ?

The solutions to the equation solvefor m,m^2-15m+56=0 are m=8,m=7

Find the zeros of solvefor m,m^2-15m+56=0

The zeros of solvefor m,m^2-15m+56=0 are m=8,m=7

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m, m^{2} - 15 m + 56 = 0

m = 8, m = 7

Solution steps

m^{2} - 15 m + 56 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 15 ) \pm ( - 15 ) ^{2} - 4 \cdot 1 \cdot 56}{2 \cdot 1}

(- 15)^{2} - 4 \cdot 1 \cdot 56 = 1

m_{1, 2} = \frac{- ( - 15 ) \pm 1}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- ( - 15 ) + 1}{2 \cdot 1}, m_{2} = \frac{- ( - 15 ) - 1}{2 \cdot 1}

m = \frac{- ( - 15 ) + 1}{2 \cdot 1} : 8

m = \frac{- ( - 15 ) - 1}{2 \cdot 1} : 7

The solutions to the quadratic equation are:

m = 8, m = 7

x^{2} + 18 x - 71 = - 8

10 - 2 x = 5^{2} - x^{2}

(k + 1) (k - 1) = 8

x^{2} + \frac{2}{3} a x + (- \frac{a ^{2}}{2} + 1) = 0

x (x - 5) - 4 (3 - x) = 0

What are the solutions to the equation solvefor m,m^2-15m+56=0 ?
The solutions to the equation solvefor m,m^2-15m+56=0 are m=8,m=7
Find the zeros of solvefor m,m^2-15m+56=0
The zeros of solvefor m,m^2-15m+56=0 are m=8,m=7