What are the solutions to the equation x(x-5)-4(3-x)=0 ?

The solutions to the equation x(x-5)-4(3-x)=0 are x=4,x=-3

Find the zeros of x(x-5)-4(3-x)=0

The zeros of x(x-5)-4(3-x)=0 are x=4,x=-3

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x (x - 5) - 4 (3 - x) = 0

x = 4, x = - 3

Solution steps

x (x - 5) - 4 (3 - x) = 0

Expand

x (x - 5) - 4 (3 - x) : x^{2} - x - 12

x^{2} - x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 12 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 12) = 7

x_{1, 2} = \frac{- ( - 1 ) \pm 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 7}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 7}{2 \cdot 1}

x = \frac{- ( - 1 ) + 7}{2 \cdot 1} : 4

x = \frac{- ( - 1 ) - 7}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

x = 4, x = - 3

a, (a^{2} + 1) (b^{2} + 4) = 10 ab - 5

1 = \frac{x ^{2}}{4}

x^{2} + 20 x + 28 = 9

6 x^{2} + 17 x + 7 = 0

2 0^{2} + 2 0^{2} = x^{2}

What are the solutions to the equation x(x-5)-4(3-x)=0 ?
The solutions to the equation x(x-5)-4(3-x)=0 are x=4,x=-3
Find the zeros of x(x-5)-4(3-x)=0
The zeros of x(x-5)-4(3-x)=0 are x=4,x=-3