What are the solutions to the equation (x^2)/5-(4x)/5 =1 ?

The solutions to the equation (x^2)/5-(4x)/5 =1 are x=5,x=-1

Find the zeros of (x^2)/5-(4x)/5 =1

The zeros of (x^2)/5-(4x)/5 =1 are x=5,x=-1

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\frac{x ^{2}}{5} - \frac{4 x}{5} = 1

x = 5, x = - 1

Solution steps

\frac{x ^{2}}{5} - \frac{4 x}{5} = 1

Multiply both sides by

5

x^{2} - 4 x = 5

Move

5

to the left side

x^{2} - 4 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 5 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 5) = 6

x_{1, 2} = \frac{- ( - 4 ) \pm 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 6}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 6}{2 \cdot 1}

x = \frac{- ( - 4 ) + 6}{2 \cdot 1} : 5

x = \frac{- ( - 4 ) - 6}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

x = 5, x = - 1

2 = - x^{2}

a, f (a + 7) = (a + 7)^{2} + 1

5 x^{2} - 10 x - 75 = 0

s^{2} + 6 s + 36.9 = 0

- 2 x^{2} + 3 x - 1

What are the solutions to the equation (x^2)/5-(4x)/5 =1 ?
The solutions to the equation (x^2)/5-(4x)/5 =1 are x=5,x=-1
Find the zeros of (x^2)/5-(4x)/5 =1
The zeros of (x^2)/5-(4x)/5 =1 are x=5,x=-1