What are the solutions to the equation 5x(x-3)=2 ?

The solutions to the equation 5x(x-3)=2 are x=(15+sqrt(265))/(10),x=(15-sqrt(265))/(10)

Find the zeros of 5x(x-3)=2

The zeros of 5x(x-3)=2 are x=(15+sqrt(265))/(10),x=(15-sqrt(265))/(10)

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5 x (x - 3) = 2

x = \frac{15 + 265}{10}, x = \frac{15 - 265}{10}

Decimal Notation

x = 3.12788 \dots, x = - 0.12788 \dots

Solution steps

5 x (x - 3) = 2

Expand

5 x (x - 3) : 5 x^{2} - 15 x

5 x^{2} - 15 x = 2

Move

2

to the left side

5 x^{2} - 15 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 15 ) \pm ( - 15 ) ^{2} - 4 \cdot 5 ( - 2 )}{2 \cdot 5}

(- 15)^{2} - 4 \cdot 5 (- 2) = 265

x_{1, 2} = \frac{- ( - 15 ) \pm 265}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 15 ) + 265}{2 \cdot 5}, x_{2} = \frac{- ( - 15 ) - 265}{2 \cdot 5}

x = \frac{- ( - 15 ) + 265}{2 \cdot 5} : \frac{15 + 265}{10}

x = \frac{- ( - 15 ) - 265}{2 \cdot 5} : \frac{15 - 265}{10}

The solutions to the quadratic equation are:

x = \frac{15 + 265}{10}, x = \frac{15 - 265}{10}

456.4 = 0.68 \cdot 100 \cdot X \cdot 1.79 \cdot (4.69 - 0.4 \cdot X)

0.25 = - 0.5 x^{2} + x

7^{2} + 1^{2} = c^{2}

X \cdot (1 - 0.59 \cdot X) = 0.14462

(- x - 4) (4 x - 2 + 3) = - (6 x - 8) + (2 x - 4 + 3)

What are the solutions to the equation 5x(x-3)=2 ?
The solutions to the equation 5x(x-3)=2 are x=(15+sqrt(265))/(10),x=(15-sqrt(265))/(10)
Find the zeros of 5x(x-3)=2
The zeros of 5x(x-3)=2 are x=(15+sqrt(265))/(10),x=(15-sqrt(265))/(10)