What are the solutions to the equation (-x-1)^2=0 ?

The solutions to the equation (-x-1)^2=0 are x=-1

Find the zeros of (-x-1)^2=0

The zeros of (-x-1)^2=0 are x=-1

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(- x - 1)^{2} = 0

x = - 1

Solution steps

(- x - 1)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

Solve

- x - 1 = 0 : x = - 1

The solution to the quadratic equation is:

x = - 1

x, f (x yz) = x^{2} + y^{2} + z^{2}

\frac{1}{2} x^{2} + 5 x = - 17

y^{2} - 9 y - 18 = 0

x^{2} - 83 x + 169 = 0

40 = \frac{( 0.0826 ) ( 0.015 ) ( 200 ) ( x ) ^{2}}{( 0.1 ) ^{5}}

What are the solutions to the equation (-x-1)^2=0 ?
The solutions to the equation (-x-1)^2=0 are x=-1
Find the zeros of (-x-1)^2=0
The zeros of (-x-1)^2=0 are x=-1