What are the solutions to the equation x^2+20x-400=0 ?

The solutions to the equation x^2+20x-400=0 are x=10(sqrt(5)-1),x=-10(1+sqrt(5))

Find the zeros of x^2+20x-400=0

The zeros of x^2+20x-400=0 are x=10(sqrt(5)-1),x=-10(1+sqrt(5))

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x^{2} + 20 x - 400 = 0

x = 10 (5 - 1), x = - 10 (1 + 5)

Decimal Notation

x = 12.36067 \dots, x = - 32.36067 \dots

Solution steps

x^{2} + 20 x - 400 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 1 \cdot ( - 400 )}{2 \cdot 1}

2 0^{2} - 4 \cdot 1 \cdot (- 400) = 205

x_{1, 2} = \frac{- 20 \pm 20 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 20 + 20 5}{2 \cdot 1}, x_{2} = \frac{- 20 - 20 5}{2 \cdot 1}

x = \frac{- 20 + 20 5}{2 \cdot 1} : 10 (5 - 1)

x = \frac{- 20 - 20 5}{2 \cdot 1} : - 10 (1 + 5)

The solutions to the quadratic equation are:

x = 10 (5 - 1), x = - 10 (1 + 5)

10 x^{2} - 33 x + 20 = 0

4 x^{2} - 36 x + 81

1.36 x^{2} + 27.8 x + 304 = 500

(400 + j^{1000}) I^{2} - j^{90} I^{1} = 0

49 x^{2} - 60 = 0

What are the solutions to the equation x^2+20x-400=0 ?
The solutions to the equation x^2+20x-400=0 are x=10(sqrt(5)-1),x=-10(1+sqrt(5))
Find the zeros of x^2+20x-400=0
The zeros of x^2+20x-400=0 are x=10(sqrt(5)-1),x=-10(1+sqrt(5))